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soal-turunan-ketiga-perkalian-fungsi-aljabar-trigonometri

Soal Turunan Ketiga Perkalian Fungsi Aljabar dan Trigonometri

Soal

Diketahui $f(x)=x\sin 2x$

tentukan:

a. $f'''(x)$

b. $f'''(\frac{\pi}{2})$

Jawaban a \begin{align*} f'(x)&=\sin 2x+2x\cos 2x\\ f''(x)&=2\cos 2x+2\cos 2x-4x\sin 2x\\ f'''(x)&=-4\sin 2x-4\sin 2x-(4\sin 2x+8x\cos 2x)\\ &=-12\sin 2x-8x\cos 2x \end{align*}

Jawaban b \begin{align*} f'''(\frac{\pi}{2})&=-12\sin\pi-8\left(\frac{\pi}{2}\right)\cos\pi\\ &=-8\left(\frac{\pi}{2}\right)(-1)\\ &=4\pi \end{align*}

soal-turunan-ketiga-perkalian-fungsi-aljabar-trigonometri.txt · Last modified: 06/04/2018 09:32 by Sopandi Ahmad